# The temperature outside is -16 degrees fahrenheit. then the temperature rises 20 degrees. what is the current outdoor temperature?

thanks

Step-by-step explanation:

## Related Questions

Your relay team competes in the 4 x 400 meter relay. The individual times for your four member team are 56.25, 59.89, 58.55, and 55.48 seconds. What is the total relay time for the team?

The total relay time for the team is 230.17 seconds.

Given information:

Your relay team competes in the 4 x 400 meter relay. The individual times for your four-member team are 56.25, 59.89, 58.55, and 55.48 seconds.

Calculation of total relay time:

= 56.25 + 59.89 + 58.55 + 55.48

= 230.17 seconds

230.17 seconds

1. Which ordered pairs are a solution to the equation? y = 3x - 4

options:

(4,2)

(1, -1)

(-1, -7)

(2, 2)
2.Which ordered pairs are a solution to the equation?

y = 4 - 2x
options:

(-1,2)

(0,4)

(-1,6)

(1,6)

For the first question the answer is (2,2) and for the second question the answer is (0,4)

Have to be positive on answer i cant fail this test i just need 2 answers...will give you a metal 1. (–10x3 + 30x – 20) ÷ (–5x + 5) (1 point)2x2 – 2x + 4
–2x2 – 2x – 4
–2x2 + 2x + 4
2x2 + 2x – 4
2. The width w of a rectangular swimming pool is x + 4. The area A of the pool is 2x3 – 29x + 12. What is an expression for the length of the pool? (1 point)2x2 + 8x +3
2x2 – 8x – 3
2x2 – 8x + 3
2x2 + 8x – 3

2x²  +2x  -4
_______________
-5x+5I -10x³ +0x² +30x -20
-10x³ +10x²
----------------
-10x³+30x
-10x² +10x
-----------------
20x-20
20x-20
------------
0
The answer for question #1 is  D,   2x²  +2x  -4

Use the same method to find answer for #2. The answer I got is 2x²-8x+3, C

Consider the line parameterized by x = 5 − 4t, y = 3 + 8t, z = 10t. find an equation of a plane so that the plane is perpendicular to the line and through the point (2, 5, 1).

2x-4y-5z +21 =0 is the equation.

Step-by-step explanation:

Given the line can be written as

The line has direction ratios (-4, 8, 10)

Since the plane is perpendicular to this line, this line is normal to the plane.

It passes through (2,5,1)

Hence plane will have equation as

-4(x-2)+8(y-5)+10(z-1) =0 Or

-4x+8y+10z +8-40-10 =0

4x-8y-10z +42 =0

Divide by 2

2x-4y-5z +21 =0