MATHEMATICS
MIDDLE SCHOOL

Answer: I think you mean mL as in milliliters

milli=thousandths

So 1,000 milliliters=1 liter

So yes, that means that 10L is greater than 1,000 milliliters

10L > 1,000mL (1mL)

milli=thousandths

So 1,000 milliliters=1 liter

So yes, that means that 10L is greater than 1,000 milliliters

10L > 1,000mL (1mL)

MIDDLE SCHOOL

How do u know that the sum of -2(3/4) and 5/6 is rational?

Any multiplication or addition of rational numbers (regardless of sign) will always give a rational result.

MIDDLE SCHOOL

HElp me with this one but not with a big processs justa little one 8. Think of another quadratic equation that has two (2) real number solutions. Write the

equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your

answer.

9. Think of another quadratic equation that has one (1) real number solution. Write the

equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your

answer.

10. Think of another quadratic equation that has no (0) real number solutions. Write the

equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your

answer.

So 2 real solutions

just write 2 factors and expand

(x-3)(x-4)=0

x^2-7x+12=0

discriminant is when you have b^2-4ac

so subsitute

ax^2+bx+c=0

a=1

b=-7

c=12

-7^2-4(1)(12)

49-48=1

discriminant=1

one real solution would be

(x-1)(x-1)=0

x^2-2x+1=0

discriminant=-2^2-4(1)(1)=4-4=0

discriminant=0

no real solutions has the discriminant less than zero

let's say that b=1 and c=20 and a=1

basically, we need a set of numbers where b^2 is less than 4acso

1^2-4(1)(20)=1-80=-79

then we subsitute

x^2+x+20=0

just write 2 factors and expand

(x-3)(x-4)=0

x^2-7x+12=0

discriminant is when you have b^2-4ac

so subsitute

ax^2+bx+c=0

a=1

b=-7

c=12

-7^2-4(1)(12)

49-48=1

discriminant=1

one real solution would be

(x-1)(x-1)=0

x^2-2x+1=0

discriminant=-2^2-4(1)(1)=4-4=0

discriminant=0

no real solutions has the discriminant less than zero

let's say that b=1 and c=20 and a=1

basically, we need a set of numbers where b^2 is less than 4acso

1^2-4(1)(20)=1-80=-79

then we subsitute

x^2+x+20=0

MIDDLE SCHOOL

Could two lines with negative slope be perpendicular

No because for a line to be perpendicular to the other, it has to be its negative reciprocal

HIGH SCHOOL

A regular n-gon has an interior angle and an exterior angle with equal measures. What is the value of n?

Wouldn’t this be a square? Then the interior and exterior angles would each be 90 degrees, so I think the answer would be n=4 then.