# Jamal is 167 cm tall which expression expression finds jamals height in dekametres A.167 times 100 B.167 times 1000 C.167 divided by 100 D.167 divided by 1000

167 cm = 1.67m
1.67m = 0.167dm

D. 167/1000 = 0.167

## Related Questions

What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5? y = x – 8
y = x + 1
y = x + 1
y = x + 10

The slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5 will be y = (3/2)x+ 10.

What is the slope?

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

It is given that,

2x+3y = -5 ------- (1)

As we know that the standard form of the equation of a line is,

y =mx +c

Rearrange the above equation 1 in the standard form as

y = (-5/3) -(2/3)x

Comparing the equation we get,

m= -2/3

The product of the slopes of the two lines is -1 if they are perpendicular.

Let m₂ be the slope of the necessary line equation. As a result,

m×m₂ = -1

m₂ = 3/2

The slope-intercept form of the equation of the line that passes through the point (–6, 1) having slope  3/2 is,

y =(3/2)x+10

Thus, the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5 will be y = (3/2)x+ 10.

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The correct answewr choice is y = 3/2x + 10 (D)

Step-by-step explanation:

I just took the Algebra quiz.

callie spent 3/4 hour on a science report and 1/3 hour on a social studies report. What fraction of an hour longer did she spend on the science report ?

3/4+1/3=9/12+4/12=13/12  of an hour

13/12= 1 1/12

lance lived in portugal and brazil for a total of 14 months to learn Portuguese. He learned an average of 130 new words per month when he lived in portugal, and an average of 150 new words per month when he lived in brazil. in total, he learned 1920 new words. write a system of equations to represent this situation. use x to represent portugal and y to represent brazil

He lived in Portugal 9 months and Brazil 5 months.

x = months in Portugal
y = months in Brazil

x + y = 14
130x + 150y = 1920

In the first equation, we will isolate x by subtracting y from both sides:
x + y - y = 14 - y
x = 14 - y

Now we will substitute this into the second equation:
130(14 - y) + 150y = 1920

Using the distributive property,
130*14 - 130*y + 150y = 1920
1820 - 130y + 150y = 1920

Combining like terms,
1820 + 20y = 1920

Subtract 1820 from both sides:
1820 + 20y - 1820 = 1920 = 1820
20y = 100

Divide both sides by 20:
20y/20 = 100/20
y = 5

Now substitute this back into the first equation:
x + 5 = 14
x + 5 - 5 = 14 - 5
x = 9

He lived in Portugal 9 months and Brazil 5 months.

a) 3 2/3x-4/5(x- 3 3/4)

b) 2 1/4x+(4 1/3x-7 4/5) divided by 2 3/5

c) 8x-1 1/7 (1 1/3x-12)

d) 11 4/7x+(5x- 2 2/5)