PHYSICS
MIDDLE SCHOOL

3. The weight of the bowling ball is greater; therefore, its inertia is greater.

4.The weight of the bowling ball is greater; therefore, its inertia is lower.

Answer: #1 is a true statement anywhere, any time.

#3 is a true statement whenever the bowling ball

and the golf ball are both on the same planet.

#3 is a true statement whenever the bowling ball

and the golf ball are both on the same planet.

HIGH SCHOOL

The portion of a light ray that falls on a surface is a/an A. reflected ray.

B. diffuse reflection.

C. specular reflection.

D. incident ray.

So we want to know what is a light ray that falls on a surface. The incident ray that fallls on a surface can then fe reflected, refracted or transmitted. The angle in which the incident ray is must be the same as the angle of a refracted light ray. So the correct answer is D.

D. incident ray, i just took the test yesterday

HIGH SCHOOL

a person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of 18 m/s. The cliff is 52 m above the water's surface. With what speed did it strike the water?

If a person standing at the edge of a seaside cliff kicks a stone over the edge, the speed with which the stone strike the water is 36.65 m/s.

Given the following data:

- Initial horizontal velocity = 18 m/s (since the stone was kicked over the edge).

- Vertical displacement = 52 meters

- Initial vertical velocity = 0 m/s

We know that acceleration due to gravity (a) is equal to 9.8 meter per seconds square.

First of all, we would determine the vertical component of the velocity by using the third equation of motion;

Where:

- V is the final speed.

- U is the initial speed.

- a is the acceleration.

- S is the displacement.

Substituting the given parameters into the formula, we have;

Vertical component of velocity = 31.92 m/s

To find the speed with which the stone strike the water, we would calculate the resultant speed by doing a vector addition of the horizontal component of the velocity and the vertical component of the velocity;

Speed = 36.65 m/s

Read more: brainly.com/question/8898885

Answer:

Speed with which it strike the water = 36.66 m/s

Explanation:

Horizontal component of velocity = 18 m/s

We need to find vertical component of velocity.

Considering vertical motion of stone

Initial velocity, u = 0 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 52 m

We have equation of motion v² = u² + 2as

Substituting

v² = u² + 2as

v² = 0² + 2 x 9.81 x 52

v = 31.94 m/s

Vertical component of velocity = 31.94 m/s

Speed with which it strike the water = 36.66 m/s

COLLEGE

Please select the word from the list that best fits the definition The part of the mantle called the _____ is made of soft rock that bends like plastic.

Asthenosphere

Explanation:

The asthenosphere is the upper part of the Earth's mantle. Located between 80 and 200 km of depth, it is a very viscous region. Given the condition of temperature and pressure in the asthenosphere, rocks in this region are very ductile, brittle and they can be bend very easily. Seismic waves pass slower through the asthenosphere than other regions of the mantles, due to the presence of these soft rocks.

Answer: The part of the mantle called the Asthenosphere is made of soft rock that bends like plastic

Explanation:

Layer lies just below the layer of lithosphere (rigid layer made by the crust and uppermost layer of the mantle). This include less rigid rocks than above which bends like plastic.

This soft layer is known as Asthenosphere.

HIGH SCHOOL

Sharks and related fish can sense the extremely weak electric fields emitted by their prey in the surrounding waters. These detectors, located in their noses and called ampullae, are so sensitive they can detect a voltage gradient of 1 ?V across1 cm of seawater. How far apart would you have to place the poles of a 1.5 V battery to achieve the same electric field? (Choose one)

1) 6.7×10-9 m

2) 1.5×10-2 m

3) 1.5×10-6 m

4) 1.5×104 m

Answer:

2) 1.5 * 10^(-2) m

Explanation:

Electric field is given in terms of Electric potential as:

E = V/r

Where V = electric potential

r = distance

E = 1V / 0.01m = 100 Vm

If the electric field is the same and electric potential is now 1.5V, we have that:

r = V/E

r = 1.5/100

r = 1.5 * 10^(-2) m