# (Square root) 550. In radical expression. Please explain steps! Thank you!

## Related Questions

A packet of crips weighs 32 grams to the nearest gram. A multipack of crisps contain 10 packets. work out the least and greatest weights of the multipack. you can ignore the weight of the multipack wrapper. its to do with upper and lower bounds​

The least and the greatest weights are 315 grams and 325 grams

Step-by-step explanation:

* Lets explain what is the upper and lower bounds

- The lower bound is the smallest value that would round up to the

estimated value.

- The upper bound is the smallest value that would round up to the next

estimated value.

- Ex: a mass of 70 kg, rounded to the nearest 10 kg, has a lower

bound of 65 kg, because 65 kg is the smallest mass that rounds to

70 kg. The upper bound is 75 kg, because 75 kg is the smallest mass

that  would round up to 80 kg, then 65 ≤ weight < 75

- So to understand how to find them divide the nearest value by 2

and then subtract it and add it to the approximated value

* Lets solve the problem

- A packet of crisps weighs 32 grams to the nearest gram

- The nearest value is 1 gram

∴ 1 ÷ 2 = 0.5

- To find the lower bound subtract 0.5 from the approximated value

∵ The approximated value is 32

∴ The lower bound = 32 - 0.5 = 31.5 grams

- To find the upper bound add 0.5 from the approximated value

∵ The approximated value is 32

∴ The upper bound = 32 + 0.5 = 32.5 grams

∴ 31.5 ≤ weight of one packet < 32.5

∵ A multipack of crisps contain 10 packets

- To find the least and greatest weights of the multipack multiply the

the lower bound and the upper bound by 10

∵ The least value of one packet is 31.5

∴ The least weight of the mulipack = 31.5 × 10 = 315 grams

∵ The greatest value of one packet is 32.5

∴ The greatest weight of the mulipack = 32.5 × 10 = 325 grams

∴ 315 ≤ weight of multipack < 325

* The least and the greatest weights are 315 grams and 325 grams

How do you multiply/divide rational numbers with variables?

To multiply, first find the greatest common factors of the numerator and denominator. Next, regroup the factors to make fractions equivalent to one. Then, multiply any remaining factors. To divide, first rewrite the division as multiplication by the reciprocal of the denominator. Hope this helped.

The area is (2x + 15) square centimeters. The ratio of the shaded region to the unshaded region is 3 : 2.
Write an algebraic expression for the area of the shaded region in terms of x.

Step-by-step explanation:

Let be the shaded area and be the unshaded area, then we know that

(1).

and

(2).

We solve for in the first equation and get:

and put this into the second equation and get:

Dave has \$15 to spend on an 8\$ book and two birthday cards (c) for his friends how much can he spend on each card if he buys the same card for each friend