MATHEMATICS
HIGH SCHOOL

Answer: K = Kevin's age

D = Daniel's age

K = 3D

K - 4 = 5(D - 4)

Plug in 3D for the K values in the second equation.

3D - 4 = 5(D - 4) Use the Distributive Property

3D - 4 = 5D - 20 Add 4 to both sides

3D = 5D - 16 Subtract 5D from both sides

-2D = -16 Divide both sides by -2

D = 8

Now, plug that D value into the original equation.

K = 3D Plug in the D value

K = 3(8) Multiply

K = 24

Finally, you can double check your math.

4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24.

So, Kevin is 24.

D = Daniel's age

K = 3D

K - 4 = 5(D - 4)

Plug in 3D for the K values in the second equation.

3D - 4 = 5(D - 4) Use the Distributive Property

3D - 4 = 5D - 20 Add 4 to both sides

3D = 5D - 16 Subtract 5D from both sides

-2D = -16 Divide both sides by -2

D = 8

Now, plug that D value into the original equation.

K = 3D Plug in the D value

K = 3(8) Multiply

K = 24

Finally, you can double check your math.

4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24.

So, Kevin is 24.

Answer: K=kevin age

d=daniel ae

k is 3 times d

k=3d

4 years ago (k-4 and d-4)

kevin was 5 times as old as dan

k-4=5(d-4)

we have

k=3d

and

k-4=5(d-4)

sub 3d for k in second euaiton

3d-4=5(d-4)

3d-4=5d-20

minus 3d both sides

-4=2d-20

add 20 both sides

16=2d

divide 2

8=d

sub back

k=3d

k=3(8)

k=24

kevin is 24

d=daniel ae

k is 3 times d

k=3d

4 years ago (k-4 and d-4)

kevin was 5 times as old as dan

k-4=5(d-4)

we have

k=3d

and

k-4=5(d-4)

sub 3d for k in second euaiton

3d-4=5(d-4)

3d-4=5d-20

minus 3d both sides

-4=2d-20

add 20 both sides

16=2d

divide 2

8=d

sub back

k=3d

k=3(8)

k=24

kevin is 24

MIDDLE SCHOOL

what is the greatest place value position where the digits differ? what does that mean if we use it in decimal?

The Tenths place because it's the first

HIGH SCHOOL

In an isosceles trapezoid, the longest base is 11", a leg is 5", and the height is 4". Find the length of the shorter base of the trapezoid.

TeUpon examination of the dissection of the trapezoid on each side, we can see that we can make out two isosceles triangles on each side. The angle on the corners of the base can be determined by sine function. we can also use pythagorean theorem, in which the other length is equal to 3". This leaves the shorter base equal to 11-2*3 equal to 5"

MIDDLE SCHOOL

-2/3 (1/2 + k) =-55/39

Find the value of "K"

least common multiple (6,3,39) = 78

least common multiple (6,3,39) = 78

HIGH SCHOOL

What is the simplified fraction is equal to 0.53 ?

.53= 53/100

53/100 cannot be simplified so the answer is 53/100

53/100 cannot be simplified so the answer is 53/100