# On a bike trip across the United States,Rodney notes that he covers about 190 miles every 4 days.If he continues at this rate,use a ratio table to determine about how many miles he could bike in 6 days.

47.5x6=285

He can bike 285 miles in 6 days

## Related Questions

Negative six plus twenty-one equal what

15

Step-by-step explanation: you can  move around the equation from -6+21

to 21-6 and still get the same answer

-6+21 = 15

15 is the answer because you subtract and then put the greater no. sign.

How do you solve 3x-1/4=-5/11

Translate the phrase into an algebraic expression 9 more than c

c + 9.

Step-by-step explanation:

That is simply c + 9. More means 'plus'.

Step-by-step explanation:

x = c + 9

An article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of a poll, showed that 46% would like more discussion about the family's financial situation, 37% would like to talk about school, and 30% would like to talk about religion. These and other percentages were based on a national sampling of 531 teenagers. Estimate the proportion of all teenagers who want more family discussions about school. Use a 99% confidence level.

From the information given, the 99% confidence interval estimate of the proportion of all teenagers who want more family discussions about school is (0.316, 0.424).

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the z-score that has a p-value of .

The information given are as follows:

• Sample size of .
• Sample proportion of .

99% confidence level

So , z is the value of Z that has a p-value of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval estimate of the proportion of all teenagers who want more family discussions about school is (0.316, 0.424).

A similar problem is given at brainly.com/question/15043877

Confidence Interval for the proportion of all teenagers who want more family discussions about school is ( 31.6% , 42.4% )

Step-by-step explanation:

Given:

Number of teenagers in the sample , n = 531

Percentage of people like more discussion about family's financial situation = 46%

Percentage of people like more discussion about school, = 37%

Percentage of people like more discussion about religion = 30%

To find:  Confidence Interval for the proportion of all teenagers who want more family discussions about school

Level of confidence, α = 100 - 99 = 1% = 0.01

We know that

Critical Value for given level of significance, = 2.58

The Standard Deviation,

The Required Confidence Interval is,

Hence the Require confidence interval is ( 0.316 , 0.424 ).

Therefore, Confidence Interval for the proportion of all teenagers who want more family discussions about school is ( 31.6% , 42.4% )