# Ohm's law is represented by the equation I = V/R. Explain how the current would change if the amount of resistance decreased and the voltage stayed the same.

Answer: The current is inversely proportional to the resistance, so as the resistance decreases, the amount of current increases.

When resistance is decreased and voltage remains the same.

Explanation:

## Related Questions

The inverse square law applies to: Intensity of sound
Gravitational Force
Intensity of light
Electric Force
Magnetic Force

Intensity of sound

Gravitational Force

Intensity of light

Electric Force

Explanation:

As we know that inverse square law will depends on the square of the distance inversely

So for

Intensity of sound or intensity of Light for very small size source we can say intensity will be defined as power per unit area.

So we can say

Now similarly we know that gravitational force is given as

also we know that electrostatic force is given as

so all above are following inverse square law

There are more correct choices on the list than incorrect ones.

The inverse square law applies to

-- the intensity of sound from a small source

-- the Gravitational Force

-- the Intensity of light from a small source

-- the Electric Force  from a point charge or a small charge.

It doesn't apply to the Magnetic Force.

For a particular reaction, the change in enthalpy is 51kJmole and the activation energy is 109kJmole. Which of the following could NOT be the change in enthalpy (ΔH) and the activation energy (Ea), respectively, for the catalyzed reaction? Select all that apply.

given,

change in enthalpy = 51 kJ/mole

change in activation energy = 109 kJ/mole

when a reaction is catalysed change in enthalpy between the product and the reactant does not change it remain constant.

where as activation energy of the product and the reactant decreases.

example:

ΔH = 51 kJ/mole

E_a= 83 kJ/mole

here activation energy decrease whereas change in enthalpy remains same.

The phrase positive to positive negative to ground is correct when jump starting a car true or false

Explanation:Jump starting a car is a process of starting a car whose battery is Dead,which means it doesn't have enough battery life to start a Car.

The process involves bringing both cars close to each other and Connecting the positive side of a good battery to the positive side of the Dead battery using a JUMPER CABLES,

Connect the positive cable to the positive side of the working battery,

Connect the Negative cable to the Negative side of the working battery,

Finally,connect the Negative cable to a grounded meta part of the car we want to JUMP START.

The largest driving force for pulling fluid from the interstitial spaces back into the capillaries is