# A non-ideal 12.2 V battery is connected across a resistor R. The internal resistance of the battery is 1.9Ohm. Calculate the potential difference across the resistor for the following values. R = 100 Ohm Express the potential difference in volts to two significant figures. R = 10 Ohm Express the potential difference in volts to two significant figures. R = 2 Ohm Express the potential difference in volts to two significant figures. Find the current through me battery for R = 100 Ohm Express your answer in amperes to two significant figures. Find the current through me battery for R = 10 Ohm Express your answer in amperes to two significant figures.

R=100 Ohm, V=11.97 volts and I=0.12 amperes

R=10 Ohm, V=10.25 volts and I=1.20 amperes

R=2 Ohm, V=6.26 volts

Explanation:

The potential difference (voltage) of a battery with internal resistance is:

(1)

with the electromotive force (the voltage the batteries say to has) , I the current and r the internal resistance. By Ohm's law the current that passes through the resistor is:

(2)

using (2) on (1):

solving for V:

(3)

R=100 Ohm

R=10 Ohm

R=2 Ohm

Because we have now the values of I on the circuit (is the same through all the components because is a series circuit)

We use back substitution on (1) to find the current:

R=100 Ohm

R=10 Ohm

## Related Questions

What are the effects of noise?​

Noise making has led to loss on hearing.

Explanation:

Supposing you like engaging in parties because of the noise of the sound system it can cause loss on hearing if continued for long

Which best explains the purpose of the rhetorical device used in the following sentences?We must learn from our mistakes. We must keep our sights on our goal. We must persevere.

A.To build the author's ethos by referring to credible sources
B.To create a memorable image by comparing two unlike objects
C.To prove a point by highlighting the obvious
D.To make the main points more memorable through repetition

The correct answer should be D. To make the main points more memorable through repetition.

This isn't appealing to ethos because ethos is appealing to credibility. It is questionable whether or not the image itself is memorable or not.

Repetition and parallelisms in speeches are used to make something more memorable and quotable. It is supposed to persuade you and this kind of sentence manipulation enables good diction.

To make the main points more memorable through repetition

Explanation:

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Some of the fastest dragsters do not race for more than 300-400m for safety reasons. Consider such a dragster in this problem, starting a race at rest. After the light turns green, the dragster completes a 400 m race in a time t= 6.8 s. If the dragster could continue with this average acceleration, what would its speed be, in miles per hour, after it has travelled a total distance of 1.6 km (~ 1 mile)?

The distance traveled by the dragster if the race continues till 1.6 km is 526.3234 miles/h.

Given to us

The distance traveled by the dragster, s = 400 m

Time taken by the dragster to complete the race, t = 6.8 s

What is the acceleration of the dragster?

The acceleration of the dragster can be found using the second equation of motion,

When the race starts the initial velocity of the dragster was 0, as the dragster was at rest, therefore, u =0

substitute the value,

a = 17.3 m/s²

Thus, the acceleration of the dragster is 17.3 m/s².

What would be the velocity of the dragster if he traveled 1.6 km?

We can find out the final velocity of the dragster using the third equation of motion,

Substitute the values,

v = 235.287 m/s

Converting it to miles per hour

Hence, the distance traveled by the dragster if the race continues till 1.6 km is 526.3234 miles/h.

brainly.com/question/5955789

Its speed would be 374.35 miles per hour

Explanation:

For the average acceleration we use 2nd eqn of motion:

s = (Vo)t + at²

Vo = 0 m/s (since, car is initially at rest)

s = 400 m

t = 6.8 s

Therefore, eqn. becomes:

400 m = (0 m/s)(6.8 s) + a (6.8 s)²

a = 400 m/(6.8 s)²

a = 8.65 m/s²

Now, for a distance of 1.6 km = 1600 m, with same acceleration, its final speed can be found out by 3rd eqn. of motion:

2as = Vf² - Vo²

2(8.65 m/s²)(1600 m) = Vf² - (0 m/s)²

Vf = √27681.66

Vf = 166.38 m/s

Vf = (166.38 m/s)(1 mile/1600 m)(3600 s/ 1 hr)

Vf = 374.35 miles per hour