Oxalic acid can remove rust (Fe2O3) caused by bathtub rings according to the reaction Fe2O3(s) - 6H2C2O4(aq) rightarrow 2Fe(C2O4)33-(aq) - 3H2O(l) - 6H+(aq) C calculate the number of grams of rust that can be removed by 6.00 times 102 mL of a 0.100 M solution of oxalic acid.


Answer 1

Answer: The mass of rust that can be removed is 1.597 grams


To calculate the number of moles for given molarity, we use the equation:


Molarity of oxalic acid solution = 0.1255 M

Volume of solution = = 600 mL = 0.600 L    (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

For the given chemical reaction:

By Stoichiometry of the reaction:

6 moles of oxalic acid reacts with 1 mole of ferric oxide (rust)

So, 0.06 moles of oxalic acid will react with = of ferric oxide (rust)

To calculate the mass of rust for given number of moles, we use the equation:

Molar mass of rust (ferric oxide) = 159.7 g/mol

Moles of rust = 0.01 moles

Putting values in above equation, we get:

Hence, the mass of rust that can be removed is 1.597 grams

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