ENGINEERING COLLEGE

when a metal, such as lead, is oxidied (loses electrons) to form a positive ion (cation), how does he solubility change?

Answers

Answer 1
Answer:

The size of the Fe and the charge of the ion get affected due to water solubility.

What properties of iron change due to solubility.?

As metal is a solid and hard element that has positive and negative atoms. A metal such as lead has an oxide that loses the electrons from the positive ion and changes its solubility.

As PB or Lead lose electrons to become cations. The compound with the small ions tends to be less soluble than compounds with large ions. The larger ions have a higher solubility. Due to small ions being closely packed it's difficult for water to break them.

Find out more information about the metal, such as lead.

brainly.com/question/2168087.

Answer 2
Answer:

Answer: The size of the ion and the charge of the ion are the factors that affect solubility in water.

Explanation:

Lead lose electrons to become cations. Compounds with small ions tend to be less soluble than compounds with large ions. Large ions have higher solubility. This is because small ions are closely packed so it is difficult for water to break them apart.

Compounds with small ions seemingly have less solubility than those with large ions. The ions in the compound attract each other, and the water molecules attract the ions. Compounds would be soluble in water If the water molecules have a greater or higher attraction to the ions than ions have for each other.


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COLLEGE

A Carnot vapor refrigeration cycle operates between thermal reservoirs at 4°C and 30°C. The working fluid is saturated vapor at the end of the compression process and saturated liquid at the beginning of the expansion process. Determine the operating pressures in the condenser and evaporator, in bar, and the coefficient of performance for each of the following as the working fluid. (a) Refrigerant 134a (b) Refrigerant R22 (c) water (d) ammonia

Answers

Answer:

COP=10.65

a)Evaporator pressure=337.7 KPa

Condenser pressure=770.2KPa  

b)Evaporator pressure=566.1 KPa  

Condenser pressure=1192 KPa

c)Evaporator pressure= 0.81 KPa

Condenser pressure=4.024 KPa

d)Evaporator pressure= 394.84KPa  

Condenser pressure=1167.2KPa

Explanation:

Given that cycle is working under Carnot cycle and we know that Carnot cycle is the ideal cycle for vapor compression.We also know that COP of Carnot cycle does not depends on the working fluids it depends only at the temperature limits.that is why COP of all fluids will be same.

COP of Carnot cycle given as follows

Here given that  

COP=10.65

Now to find the condenser and evaporator pressure

We know that inside the wet region only one property needed to find other properties.Here given that temperature at condenser and at evaporator so the condenser and evaporator pressure will be the saturation pressure condenser and evaporator at given temperature for all fluids.

a)For refrigerant 134a

From properties table of  refrigerant 134a

Evaporator pressure=337.7 KPa   (pressure corresponding to  4°C)

Condenser pressure=770.2KPa  (pressure corresponding to  30°C)

b)For refrigerant R22

From properties table of  refrigerant R22

Evaporator pressure=566.1 KPa   (pressure corresponding to  4°C)

Condenser pressure=1192 KPa  (pressure corresponding to  30°C)

c)For refrigerant water

From properties table of  refrigerant water

Evaporator pressure= 0.81 KPa   (pressure corresponding to  4°C)

Condenser pressure=4.024 KPa (pressure corresponding to  30°C)

d)For refrigerant ammonia

From properties table of  refrigerant ammonia

Evaporator pressure= 394.84KPa   (pressure corresponding to  4°C)

Condenser pressure=1167.2KPa  (pressure corresponding to  30°C)

The coefficient of performance (COP) for each of the working fluid is equal to 10.66.

Given the following data:

Operating temperature A = 4°C to K = 273.15 + 4 = 277.15 K.

Operating temperature B = 30°C to K = 273.15 + 30 = 303.15 K.

How to determine the coefficient of performance.

In Science, the coefficient of performance (COP) is a mathematical expression that is used to show the relationship between the power output of a refrigeration system and the power input of its compressor based on temperature limits.

Mathematically, the coefficient of performance (COP) is given by this formula:

COP = 10.66.

From the thermodynamic properties table, the pressure of refrigerant 134a at a temperature of 30°C is:

  • Condenser pressure = 770.2 KPa .

From the thermodynamic properties table, the pressure of refrigerant 134a at a temperature of 4°C is:

  • Evaporator pressure = 337.7 KPa.

From the thermodynamic properties table, the pressure of refrigerant R22 at a temperature of 30°C is:

  • Condenser pressure = 1192 KPa .

From the thermodynamic properties table, the pressure of refrigerant 134a at a temperature of 4°C is:

  • Evaporator pressure = 566.1 KPa.

From the thermodynamic properties table, the pressure of water at a temperature of 30°C is:

  • Condenser pressure = 4.024 KPa .

From the thermodynamic properties table, the pressure of water at a temperature of 4°C is:

  • Evaporator pressure = 0.81 KPa.

From the thermodynamic properties table, the pressure of ammonia at a temperature of 30°C is:

  • Condenser pressure = 1167.2 KPa .

From the thermodynamic properties table, the pressure of ammonia at a temperature of 4°C is:

  • Evaporator pressure = 394.84 KPa.

Read more on coefficient of performance here: brainly.com/question/20713684

MIDDLE SCHOOL

A wheel accelerates from rest with a 4 rad/s^2. How many revolutions are experienced in 6 seconds

Answers

Answer:

Revolutions = θ = 11.47

Explanation:

Given that:

Angular acceleration = α = 4 rad/s^2

As the wheel starts from rest so, ω₀ = 0

Time = t = 6 seconds

So we have to calculate revolutions per second, we know that:

θ  =  ω₀ t + 1/2 ( α * t ^2)

By putting values:

θ = 0 * 6  + 1/2(4 * (6^2))

θ = 0 + 2* 36

θ = 72

As the rotation angle is 2π, the revolutions will be calculated as:

s = θ / 2π.

By putting values:

s = 72/2(3.14)

s = 72/6.28

s = 11.47

So, there will be 11.47 revolutions in 6 seconds.

i hope it will help you!

MIDDLE SCHOOL

Which of the following supports the idea of establishing justice? A. raising an army and a navy
B. collecting taxes
c. forming a judicial branch
D. regulating commerce

Answers

Answer:

C

Explanation:

MIDDLE SCHOOL

What type of eye protection should you use when there is dust present ? A) safety glasses
B) goggles
C) face shields

Answers

When there is dust present, a person should use Goggles.

Goggles

Goggles were indeed simply glasses that thus attach to your forehead as well as cover one's whole eye region. Swim as well as safety goggles shield our eyes, although there are modern technology as well as night vision goggles that augment or transform what you have seen.

Some glasses need to do more than keep your eyesight safe. Night vision allows people to are seeing throughout the dark, while virtual reality goggles make you appear to be in another dimension.

Thus the response above i.e., "Option B" is correct.

Find out more information about goggles here:

brainly.com/question/16468502

Answer:

B. Goggles

Explanation:

Goggles fit tightly around your face and dust will have no way of reaching your eyes, therefore it is the safest out of all the options.

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