# A mass hanging from a spring oscillates with a period of 0.35 s. Suppose the mass and spring are swung in a horizontal circle, with the free end of the spring at the pivot. What rotation frequency, in rpm, will cause the spring’s length to stretch by 15%?

66 rpm

Explanation:

The period of oscillation is given by

where  T is time period of oscillation which is given as 0.35 s, k s spring constant and m is the mass of the object attached to the spring.

Also, net force is given by

Net force=

where is the elongation, L is original length, is the angular velocity

Substituting the equation of into the above we obtain

## Related Questions

How are you able to determine if conservation of momentum occurs in each collision?

Using Newtons Second law of motion

Explanation:

Newtons Second law of motion states that the rate of change momentum of a system is directly proportional to unbalanced External force acting on it.

if we consider all colliding particles as a system we can see there is no external forces acting on the system. the forces that present here due to collision are internal forces

so As per newtons second law moment should be conserved for the colliding particles.

There is a table that is filled with lab materials. The materials include a 500-g weight, a spring scale, dynamic cart, a digital timer, a pulley, a thermometer, and a graduated cylinder. Which set of equipment would best utilize Newton's Second Law to find the mass of the dynamic cart? A) A spring scale, a timer, and the dynamic cart B) A pulley, a meter stick and the dynamic cart. C) A timer, a thermometer, a meter stick and the dynamic cart. D) A timer, a meter stick, a spring scale and the dynamic cart.

What part of an atom is responsible for producing magnetic fields