# You have an unpolarized light source and you wish to send a beam of this light with intensity Io through a number of sheets of polarizing material. You stack the sheets of polarizing material so that the axis of polarization for the last sheet is always at right angles to that of the first sheet and the transmission axis of each sheet relative to the preceding sheet is the same for every sheet. Determine the following (a) the intensity I3 of the light (in terms of I transmitted through a stack if the stack consists of three sheets of the polarizing material By what fraction is the intensity of light reduced by the first filter? How is the intensity of light after the second filter related to that after the first filter? How can you determine the angle between adjacent polarizing fters?Io (b) the intensity I4 of the light (in terms of ) transmitted through a stack if the stack consists of four sheets of the polarizing material How can you modify your work from part (a) in order to solve part (b)?Io (c) the intensity 20 of light (in terms of I) transmitted through a stack if the stack consists of twenty sheets of the polarizing material 20 How can you modify your work from part (a) in order to solve part (c)Io (d) an expression for the intensity I, of light (in terms of Io) transmitted through a stack if the stack consists of n sheets of the polarizing material 90.0 2(n - 1) が10 cos( 90.00 )2(n-1) 90.0° 2(n -1) 90.0 2n

Explanation:

a ) The angle  between the polarization axis of two adjecent sheet

= 90 / 3 = 30 degree.

The formula for intensity of polarised light from unpolarised light ( first transmission

I₁ = I₀ /2

I₀ is intensity of unpolarised light and I₁ is intensity of light after first time polarization .

The relation of I₁ and I₂ is as follows

I₂ = I₁ cos²30

= I₀/2 x3/4

=3 I₀/8

Relation between I₃ and I₂ is as follows

I₃ = I₂ cos²30

= 3I₀ / 8 x 3/4

= 9 I₀ / 32

= 0 .28 I₀

In case of stack of 4 plates

angle between two plates  = 90/4  = 22.5 degree

I₁ = I₀ /2

I₂ = I₁ cos²22.5

=  I₀ /2 x .85

I₃ = I₂ cos²22.5

= I₀ /2 x .85 x .85

= .36 I₀

## Related Questions

The strength of gravitational force is dependent on the masses of and distance between two objects. a. True
b. False

Truer words are seldom written.

If the tensile strength of the Kevlar 49 fibers is 0.550 x 106 psi and that of epoxy resin is 11.0 x103 psi, calculate the strength of the composite material that contains 79 percent by volume of Kevlar 49 fibers. The answer should be in psi with 0 decimals of accuracy.

Explanation:

Notation

represent the tensile strength for the Kevlar 49 fibers

represent the tensile strength for the epoxy resin

79% by volume is made of Kevlar 49 fibers

The rest 100-79=21% is made of epoxy resin

Tensile strength is a "measurement of the force required to pull something such as rope, wire, or a structural beam to the point where it breaks". Can be defined as "the maximum amount of tensile stress that it can take before failure".

For this case we need to use a basis of calculus since we don't know the total volume but we can assume a reference value on order to make the calculations.

If we assume a total volume of we can do the follwoing balance:

We can replace the values given:

So then the strength of the composite material is :

Which of the following are electromagnetic waves? sound waves water waves ground waves light waves`

Hello! Light waves are an example of electromagnetic waves. I hope this helps!

A pelican dives downward from a height of 35 m with an acceleration of 9.8 m/s² to grab a sardine at the surface of the ocean. How long does the dive take? OA) 0.75 s
OB) 1.9 s
OC) 2.7 s
OD 7.1 s​

The dive takes 2.673 seconds.

so OC i think

D = ViT + 1/2 at^2 If the pelican is traveling at 0 m/s vertically at t=0 then that means Vi=0Additionally, if you consider the fact that the distance traveled and acceleration is both the same direction, then sign doesn't matter: 35 = (0) x t + 1/2 (9.8) t^2

35 = 4.9t^2

7.14286 = t^2

t = 2.673s

and you round up to the whole number which would leave your answer to be > OC: 2.7s