CHEMISTRY COLLEGE

Chemistry: An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container, if the gas has a pressure of the 845mmHg at 22degrees Celsius? ​

Answers

Answer 1
Answer:

Answer:

There are 29.4 grams of oxygen in the container

Explanation:

Step 1: Data given

Volume = 20.0 L

Pressure = 845 mmHg

Temperature = 22.0 °C

Molar mass of O2 = 32 g/mol

Step 2: Ideal gas law

p*V = n*R*T

⇒ p = the pressure of the gas = 845 mmHg = 1.11184

⇒ V = the volume of the gas = 20.0 L

⇒ n = the number of moles = TO BE DETERMINED

⇒R = the gasconstant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 22°C + 273 = 295 Kelvin

n = (p*V)/(R*T)

n = (1.11184*20.0)/(0.08206*295)

n = 0.9186 moles

Step 3: Calculate mass of NO2

Mass of O2 = Moles O2 * Molar mass O2

Mass of O2 = 0.9186 moles * 32 g/mol

Mass of O2 = 29.4 grams

There are 29.4 grams of oxygen in the container


Related Questions

HIGH SCHOOL

Butane, c4h10, is a component of natural gas that is used as fuel for cigarette lighters. the balanced equation of the complete combustion of butane is 2c4h10(g)+13o2(g)?8co2(g)+10h2o(l) at 1.00 atm and 23 ?c, what is the volume of carbon dioxide formed by the combustion of 3.20 g of butane?

Answers

Molar mass of butane = 12g/mol*4+1g/mol*10=58g/mol

Mass of 2 moles of butane=2mol*58g/mol=116g

2c4h10(g)+13o2(g)->8co2(g)+10h2o(l)

116g                        8 moles

3.20g                           x

 

116g butane/8moles CO2=3.20g butane/x

x=3.20g butane*8moles CO2/116g butane=0.2207moles CO2

T=23°C=296K

PV=nRT

V=nRT/P=0.2207moles*0.082(atm*dm³/(K/mol))*296K/(1atm)=5.36dm³

HIGH SCHOOL

Which of these pairs of elements is most likely to be part of a polyatomic ion? Cr and O
K and F
Li and Br
Mg and O

Answers

Cr and O are most likely to be part of a polyatomic ion.

Cr belongs to the transition metal series in the periodic table and has vacant d-orbitals. As a result it can exist in more than one oxidation state, the most common being +6, +3 and +2. Oxygen exists in -2 oxidation state. Hence, Cr and O can combine to form different polyatomic ions like: CrO₄²⁻ and Cr₂O₇²⁻ (Cr in +6 state)

K, Li and Mg exist in only one oxidation state +1 (K and Li) and +2(Mg). F and Br exhibit an oxidation state of -1. Therefore, they are not likely to form polyatomic ions.

Ans (a) Cr and O

Cr and O I believe. I feel like I've seen it before as a polyatomic ion
HIGH SCHOOL

True or false: a mixture is always made up of a combination of elements

Answers

A mixture has lots of different elements that are not necessarily bonded to each other, like sea water has lots of dirt, animals, and plant parts in it.  Compared to a solution (strictly salt and water, which bond and ionize with each other).
HIGH SCHOOL

J.J. Thomson's experiments supported the existence of a particle that deflected away from a negative charge and toward a positive charge. Ernest Rutherford found that when positive particles were fired at gold foil, some of the particles deflected rather than passing straight through. Taken together, these experiments support our understanding of the A. Flavors or quarks
B. Structures of the atom
C. Specific gravity of gold
D. Law of Conservation of energy

Answers

B. Structures of the atom...... I hope I’m right
B. The structures of the atom
Random Questions