# A meterstick moves toward you at speed 0.60c. What length do you measure for the meterstick?

-- IF the meter stick is oriented perpendicular to the direction from
it to you, then it appears 1 meter long to you, but very very skinny.
The Lorentz contraction only applies in the direction of motion.

-- If the length of the meter stick is pointing toward you, then . . .

L = L₀ √ (1 - v²/c²)

=      √ (1 - 0.36)

=      √ (0.64)  =  0.8 meter .

## Related Questions

Two charges, q1 and q2, are separated by a certain distance r. if the magnitudes of the charges are halved and their separation is halved, then what happens to the electrical force between these two charges?

The electrical force between these two charges remains the same. In coulomb’s law, it states that the magnitude of two charges (product of two charges) is inversely proportional to the square of the distance. Since both the magnitude and the distance are halved, therefore, the change in both quantities will have no effect in the value of electrical force.

what person is responsible for providing short term care for people being transported to the hospital

Explanation:

A person responsible for providing short term care for people being transported to the hospital is a first aider. This people provide first aid to victims from the point of incident till the hospital where such victims will be properly taken care of. They only provide first treatment to the victim prior to being taken to the hospital.

Firstly Aid is therefore defined as the first treatment administered to a patient before being taken to the hospital.

The ambulance people

Recall that the differential equation for the instantaneous charge q(t) on the capacitor in an lrc-series circuit is l d 2q dt 2 + r dq dt + 1 c q = e(t). see this excerpt about lrc-series circuits. use the laplace transform to find q(t) when l = 1 h, r = 20 ω, c = 0.005 f, e(t) = 160 v, t > 0, q(0) = 0, and i(0) = 0. q(t) =

DE which is the differential equation represents the LRC series circuit where
L d²q/dt² + Rdq/dt +I/Cq = E(t) = 150V.
Initial condition is q(t) = 0 and i(0) =0.
To find the charge q(t)  by using Laplace transformation by
Substituting known values for DE
L×d²q/dt² +20 ×dq/dt + 1/0.005× q = 150
d²q/dt² +20dq/dt + 200q =150

Answer: 68852 millijoules = 16.46 calories

Explanation:

Given;

Convert 68852 millijoules to calories.

1 calorie = 4.184J = 4184millijoules

Therefore,

1 millijoule = 1/4184 calories

68852 millijoule = 68852 × 1/4184 calories

= 16.46 calories