# ¿What is the density of a rock if it has a mass of 50 g and a volume of 10 mL?

The density of rock that has a mass of 50 g and a volume of 10 mL is 5g/ml cubic.

How to find the density?

Density is like rate. It tells you how much of a thing is available for each unit another thing which contains the first thing.

Density = (Total amount available)/(total space which contains that amount)

Given that rock has a mass of 50 g and a volume of 10 mL.

Then;

Density = mass/volume

Substitute the values;

d = 50/10

d =5

Hence, The density is 5g/ml cubic.

The density of rock that has a mass of 50 g and a volume of 10 mL is 5g/ml cubic.

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D=m/v so d=50/10=5

The density is 5g/ml

It might be ml^3 (5g/ml^3) but I don’t remember

## Related Questions

(2.01) solve -2(2x + 5) - 3 = -3(x - 1)

solve -2(2x + 5) - 3 = -3(x - 1)

-4x - 10 -3  = -3x + 3
-4x - 13 = -3x + 3

-4x - 13 +3x = -3x +3

Simplify
-x - 13 = 3
-x - 13 + 13 = 3 + 13

Simplify
-x = 16

multiply both sides by (-1)
x = -16
-2(2x + 5) - 3 = -3(x - 1)...distribute thru the parenthesis
-4x - 10 - 3 = -3x + 3 ...simplify
-4x - 13 = -3x + 3...add 3x to both sides
-4x + 3x - 13 = 3 ...add 13 to both sides
-4x + 3x = 3 + 13 ...combine like terms
-x = 16 ... multiply by -1 to make x positive
x = -16

A scientist wants to find the radius, in feet, of this hemispherical dome. He found that the surface area of the entire sphere containing the dome is 294 square feet. Which equation could he use to find the dome's radius? A. r2=294 square feet ÷ 4π
B. r2=294 square feet ÷ 2π
C. r2=294 square feet ÷ π
D.r2=588 square feet ÷ 4π

The surface area of a sphere by definition is given by:
A = 4 * π * r ^ 2
Where,
Substituting the values we have:
294 = 4 * π * r ^ 2
r ^ 2 = (294) / (4 * π)
An equation that I could use to find the dome's radius is:
A. r2 = 294 square feet ÷ 4π

A. r2 = 294 square feet ÷ 4π

The radius of the hydrogen atom is 0.529x10/-10 and the radius of the nucleus is 1.2x10/-15m. Compare the radius of each by writing a ratio.

we know that

The radius of the hydrogen atom is

The radius of the nucleus is  m

the ratio is equal to

that means the radius of the hydrogen atom is 44,083.33 times the radius of the nucleus

therefore