# Lee wants to cut this piece of canvas into two rectangles that are 3×2 and 3×5. He wants the sum of the areas of the two small rectangles to be the same as the area of the large rectangle. Can he do that? Explain

Answer: First find the area of the large rectangle which is 90 by you times 3 and 3 which is 9 then you times 5 and 2 which is 10 after that u times 9 and 10 which is 90 So to make the small rectangle times 6 and 15 because 3 times 2 equals 6 and 5 times 3 equals 10 so that means the area of one small rectangle is 6 and the other rectangle us 15 then u multiple

## Related Questions

Ms. Hanson invests \$500 in the stock market. After ten years, if her investment is worth 300% of its original cost, how much will it then be worth?

WORTH = 500 + 300/100×500 =500+1500 = \$2000

HOPE THIS WILL HELP U

1500

Step-by-step explanation:

PLEASE ANSWER PRIORITIZE QUESTIONS 1. What is the length of the segment joining the points at (-1,6) and (-5,3) 2. What is the length of the segment joining the points at (-4, 1) and (3,7)

1. length of the segment = 5 units

2. length of the segment = 9.22 units

Step-by-step explanation:

To find the length of a segment joining two points (x,y) and (x',y') we always use the formula

Distance between the points = √(x-x')²+(y-y')²

In our question the given points are (-1,6) and (-5,3) the distance between them will be = √(-1+5)²+(6-3)² = √4²+3² = √16+9 =√25 = 5 Units

2. Length between the points (-4,1) and (3,7) will be = √(-4-3)²+(1-7)²

= √(-7)²+(-6)² = √49+36 = √85 = 9.22 units

You have a large jar that initially contains 30 red marbles and 20 blue marbles. We also have a large supply of extra marbles of each color. Draw a marble out of the jar. If it's red, put it back in the jar, and add three red marbles to the jar from the supply of extras. If it's blue, put it back into the jar, and add five blue marbles to the jar from the supply of extras. Do this two more times. Now, pull a marble from the jar, at random. What's the probability that this last marble is red? What's the probability that we actually drew the same marble all four times?

There is a 57.68% probability that this last marble is red.

There is a 20.78% probability that we actually drew the same marble all four times.

Step-by-step explanation:

Initially, there are 50 marbles, of which:

30 are red

20 are blue

Any time a red marble is drawn:

The marble is placed back, and another three red marbles are added

Any time a blue marble is drawn

The marble is placed back, and another five blue marbles are added.

The first three marbles can have the following combinations:

R - R - R

R - R - B

R - B - R

R - B - B

B - R - R

B - R - B

B - B - R

B - B - B

Now, for each case, we have to find the probability that the last marble is red. So

is the probability that we go R - R - R - R

There are 50 marbles, of which 30 are red. So, the probability of the first marble sorted being red is .

Now the red marble is returned to the bag, and another 3 red marbles are added.

Now there are 53 marbles, of which 33 are red. So, when the first marble sorted is red, the probability that the second is also red is

Again, the red marble is returned to the bag, and another 3 red marbles are added

Now there are 56 marbles, of which 36 are red. So, in this sequence, the probability of the third marble sorted being red is

Again, the red marble sorted is returned, and another 3 are added.

Now there are 59 marbles, of which 39 are red. So, in this sequence, the probability of the fourth marble sorted being red is . So

is the probability that we go R - R - B - R

is the probability that we go R - B - R - R

is the probability that we go R - B - B - R

is the probability that we go B - R - R - R

is the probability that we go B - R - B - R

is the probability that we go B - B - R - R

is the probability that we go B - B - B - R

So, the probability that this last marble is red is:

There is a 57.68% probability that this last marble is red.

What's the probability that we actually drew the same marble all four times?

is the probability that we go R-R-R-R. It is the same from the previous item(the last marble being red). So

is the probability that we go B-B-B-B. It is almost the same as in the previous exercise. The lone difference is that for the last marble we want it to be blue. There are 65 marbles, 35 of which are blue.

There is a 20.78% probability that we actually drew the same marble all four times

What is the product of ( x ^ ( 2 ) )/( 6 y );( 2 x )/( y ^ ( 2 ) ) and ( 3 v ^ ( 3 ) )/( 4 x );x \neq 0;y \neq 0