# (1 + 2/7) +(2 + 1/3)*x+ 3/14 +x=9

(1 + 2/7) +(2 + 1/3)*x+ 3/14 +x=9

140x = 315

x = 9

4

= 2.25

Step-by-step explanation:

## Related Questions

The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 + xz2 + yz – 24. What is the value of x? What is the value of y?

Hence, the value of x is 5 and y=29

Step-by-step explanation:

We are asked to find the product of and and equate it to the equation:

and find the values of x and y in the second equation.

The product of   and is:

Hence on comparing with  we have:

so we get that x=5, y=29

X = 5
y = 29

When you multiply the trinomial and the binomial, you get
-4z^3 + 5z^2 + 29z - 24 . The coefficient of the z^2 term is 5 and the coefficient of the z term is 29.

A commuter railway has 800 passengers a day and charges each one 2 dollars. ? For each 10 cents the fair is increased, 2 fewer people will ride the train. Express the income I from the train in terms of the ticket price p (in dollars). T/F

The income I from the train in terms of the ticket price p (in dollars) is;

I = \$(-20p² + 840p)

Number of passengers a day = 800 passengers

Charge for each passenger = \$2

We are told that for each \$0.1 there is an increase in ticket price and the number of passengers will be 2 fewer people.

Thus;

Number of passengers is now (800 - 2x)

The ticket price is now; p = \$(2 + 0.1x)

Thus;

Let us make x the subject of the formula from the price equation to get;

x = (p - 2)/0.1

x = 10p - 20

Putting 10p - 20 for x in (800 - 2x) gives;

Number of passengers = 800- 2(10p- 20)

Number of passengers = 800 - 20p + 40

Number of passengers = 840- 20p

• Income is calculated by multiplying the number of the passenger by the ticket price. Thus, if income is denoted by I, then;

I = p(840 - 20p)

I = -20p² + 840p

I= -20p^2 + 840p

Step-by-step explanation:

When the ticket price is \$2 there are 800 passengers daily, but every \$0.1 increase in ticket price the number of passengers will be decreased by 2.

You can put information into these equations of:

passenger- = (800-2x)

ticket price= p = \$2 + 0.1x

Income is calculated by multiplying the number of the passenger with the ticket price. The answer will be expressed in terms of the ticket price, so we need to remove x from the passenger equation.

p= \$2 +0.1x

p-\$2 = 0.1x

x= 10p- \$20

If  p= ticket price, the function for the number of passengers it will be:

passenger = (800-2x)

passenger = 800- 2(10p- \$20)

passenger =800- 20p+40

passenger =840- 20p

The function of I will be:

I= passenger x ticket price

I=  840- 20p * p

I= -20p^2 + 840p

What is the line that is parallel to 2x-3y=1 ? what is the slope of the line that is perpendicular to 2x-3y=1 ?

The equation of a line parallel to 2x - 3y = 1 will look exactly the same as this one, EXCEPT you'll have a different constant (i. e., a constant term not equal to 1).
1 - 2x
Solve 2x - 3y = 1 for y:   -3y = 1 - 2x, or   y = ----------
-3

in which the slope, m, is 2/3.  The slope of a line perpendicular to 2x - 3y = 1 would be the negative reciprocal of 2/3; that is -3/2 (answer)

A table that originally cost \$196 is on sale for \$160.00 what is the percent of decrease rounded to the nearest tenth ?