MATHEMATICS
MIDDLE SCHOOL

Answer:

Answer:

3x+y=13

Step-by-step explanation:

Standard form of equation is:

Ax+By=C where x and y are variables and A,B and C are constants.

Given equation is:

y-4=-3(x-3)

we have to make given equation in standard form.

simplifying given equation,we get

y-4=-3(x-3)

y-4=-3x+9

adding 4 to both sides of above equation,we get

y-4+4=-3x+9+4

y+0=-3x+13

y=-3x+13

adding 3x to both sides of above equation,we get

3x+y=3x-3x+13

3x+y=0+13

3x+y=13 is standard form of given equation where A=3,B=1 and C=13.

Answer: Y - 4 = -3x + 9

y = -3x + 13

standard form: 3x + y = 13

y = -3x + 13

standard form: 3x + y = 13

MIDDLE SCHOOL

A jet climbs at a steady rate at an angle of inclination of 0.5 degree during take-off. What will its he height be after a 2.2 km initial ascent at this angle at this angle?

Answer: Height= 0.019km

Step-by-step explanation:

Things to consider;

The distance of the jet at the angle 0.5°

The vertical distance of the jet from the ground

The horizontal distance of the jet

Using imaginary lines these three components will form a right angle triangle which provides us valuable information in calculating the height of the jet from the ground.

Using the formulae: Sine of an angle= opposite side/ hypotenuse side

Where the opposite side is the side opposite to the angle 0.5 which is the height of the jet.

The hypotenuse side is the distance of the jet at the angle 0.5

Therefore, Sine 0.5= height/ 2.2km

Height = Sine 0.5×2.2

Height = 0.0087×2.2= 0.019km

Hence the height is 0.019km

MIDDLE SCHOOL

Ella stopped at a farm stand to buy some peaches. Peaches cost $1.35 per pound at the stand. Ella bought 4 peaches that weighed 1.6 pounds in total. How much did Ella pay for the peaches? Please help and explain how you did it!

Multiply the number of peaches by the number of pounds and add the number of pounds and multiply 1.35 by the number of pounds that you added up

COLLEGE

Identify all the factors of the expression 4x2 +17x-15

The answer is =

7+17x

7+17x

MIDDLE SCHOOL

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches. Calculate the range of horn lengths for the middle 99.7% of Texas longhorn cattle.

A.

51 in.–60 in.

B.

51 in.–69 in.

C.

60 in.–73.5 in.

D.

46.5 in.–73.5 in.

Answer:

D. 46.5 in.–73.5 in.

Step-by-step explanation:

We have been given that horn lengths of Texas longhorn cattle are normally distributed.

Since the empirical rule states that about 99.7% of the population lies within the 3 standard deviation. So according to normal distribution the range for the middle 99.7% of the values is: .

Upon substituting our given values we will get,

Therefore, the range of horn lengths for the middle 99.7% of Texas longhorn cattle is 46.5 inches to 73.5 inches and option D is the correct choice.