Peter has \$4.80 in his piggy bank, consisting of dimes and quarters. If there are 33 coins in all, how many of each does he have?

10 quarters, 23 dimes

Step-by-step explanation:

Make dimes = d and quarters = q. Let the number of dimes and quarters add up to 33 and the value of the dimes and quarters add up to 4.80. The system of equations should look like:

• d + q = 33
• 0.10d + 0.25q = 4.80

Solve for d in the first equation. Subtract q from both sides.

d = 33 - q

Substitute d into the second equation.

0.10(33 - q) + 0.25q = 4.80

Distribute 0.10 inside the parentheses.

3.3 - 0.10q + 0.25q = 4.80

Combine like terms.

3.3 + 0.15q = 4.80

Subtract 3.3 from both sides.

0.15q = 1.5

Divide both sides by 0.15.

q = 10

Substitute this value of q into where we solved for d (d = 33 - q).

d = 33 - (10)

d = 23

Related Questions

The second of 2 numbers is 5 more than twice the first. Their sum is 29. Find the numbers

Call the numbers x and y. Let y be the larger number.
The second of 2 numbers is 5 more than twice the first is y = 2x+5
Their sum is 29 is x+y=29.
Substitute 2x+5 for y in the second equation.x+2x+5=29
3x=24
x=8
y = 2(8) + 5 = 21
Hope the solution helped.
Briemode!:)

So call the numbers x and z
first number=x
second number=z
second of 2 numbers (z) is = 5 more than (5+) twice the first (2x)
z=5+2x
their sum is 29
x+z=29
subsisute 5+2x for z in equation
x+5+2x=29
3x+5=29
subtract 5
3x=24
divide bboth sides by 3
x=8
subsitute 8 for x
z=5+2(8)
z=5+16
z=21

numbers are 8 and 21

How do I solve 76/35=k+31/10

76/35=k+31/10

Hope this helps!

Evan and Jose are writing an equation of the line through (4,5) 4 5 and (8,7) 8 7 . Whose solution is correct?

My solution is Y= x/2 + 3. I don't know Evan's or Jose's solution.

5/4 gallons of water fill 5/6 of a bucket. How many gallons of water fill the entire bucket

5/4 : 5/6

= 5/4 * 6/5

= 1/4 * 6/1

= 1/2 * 3/1

= 3/2 = 1 1/2 = 1.5 gallons

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