MATHEMATICS MIDDLE SCHOOL

How do i use product rule and simplfy while keeping positive exponents

Answers

Answer 1
Answer: Product rule is

so if ou have




not sure what yo mean by positive exponents, just add them

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COLLEGE

What is the completely factored form of f(x)=x3+5x2+4x−6? f(x)=(x−3)(x−(−1+i3√))(x−(−1−i3√))

f(x)=(x+3)(x−(−1+i3√))(x−(−1−i3√))

f(x)=(x+3)(x−(−1+3√))(x−(−1−3√))

f(x)=(x−3)(x−(−1+3√))(x−(−1−3√))

Answers

The factored type is the product of constants and two-dimensional terms, that is the root of a function as well as the graph's x-intercepts, and the further calculation can be defined as follows:

Given:

To find:

factored form=?

Solution:

putting the value x=-1,-2,-3...... to find the function value 0.

             

             

             

Therefore, is the factor of the function.

Let divide by the function:

compare the value by the standard equation so,

Putting value into the quadratic equation formula:

Adding the factor value that is so, the value is ""

So, the final answer is ""

Learn more:

brainly.com/question/16754415




Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
.    |  1   2  -2    0

which translates to



with remainder 0. Now by the quadratic formula,



and so


MIDDLE SCHOOL

Vertex (-2,-2) point (-3,0) in standard form of the parabola

Answers

Answer:

y=2(x+2)^2-2

Step-by-step explanation:

(h,k) --> (-2,-2)

y=ax^2+bx+c

y=a(x-h)^2+k

HIGH SCHOOL

Write the summation to estimate the area under the curve y = 1 + x2 from x = -1 to x = 2 using 3 rectangles and right endpoints

Answers

Answer:

The estimated area is 8 square units.

Step-by-step explanation:

y=f(x)=1+x²

Left point: a=x=-1

Right point: b=x=2

Range: r=b-a→r=2-(-1)→r=2+1→r=3

Width of each of the 3 equal rectangles: w=r/3→w=3/3→w=1

First right endpoint is x1=a+w→x1=-1+1→x1=0

Second right endpoint is x2=x1+w→x2=0+1→x2=1

Third right endpoint is x3=x2+w→x3=1+1→x3=2


Estimated Area: A≈A1+A2+A3


A1=w*f(x1)→A1=w*f(0)

x=0→f(0)=1+0²→f(0)=1+0→f(0)=1

A1=w*f(0)→A1=1*1→A1=1


A2=w*f(x2)→A2=w*f(1)

x=1→f(1)=1+1²→f(1)=1+1→f(1)=2

A2=w*f(1)→A2=1*2→A2=2


A3=w*f(x3)→A3=w*f(2)

x=2→f(2)=1+2²→f(2)=1+4→f(2)=5

A3=w*f(2)→A3=1*5→A3=5


A≈A1+A2+A3→A≈1+2+5→A≈8 square units


MIDDLE SCHOOL

Please help me!!!!!
find the area of a square with a side length of 24.6 km

Answers

It would be 24.6 ×24.6
it's 605.16
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