# Change the percent to a fraction 64%

0.64. All you have to do is add a 0 and a decimal to it. It's the same number. :)

64/100

Simplest form is 16/25

## Related Questions

Which of the following ordered pairs represents a solution to the linear equation y=6x-2x

The ordered pairs are not given, but they are going to be a solution if they are in the following format:

.

The equation given is:

We can simplify it:

Thus, ordered pairs (x,y) are a solution if they are in the following format:

.

A similar problem, which asks if an ordered pair is a solution of an equation, is given at brainly.com/question/10585472

Since you didn't list the points, I can only give you some example points. Then, you can select the points in your problem.

First, the equation can be simplified to just: y = 4x

Now, just select points for x, then multiply by 4 to get y.

0, 0
1, 4
2, 8
3, 12
4, 16
5, 20

In four years Cranston’s age will be the same as Terrill’s age is now. In two years time, Terrill will be twice as old as Cranston. Find their ages now.

Uuuuh...
c + 4 = t
t + 2 = 2c
c + 4 = 2c – 2
c = 2
t = 6

or

c = t - 4....................................(1)

in 2 years we have:

t + 2 = 2(c + 2)

i.........e......... t + 2 = 2c + 4

=&amp;gt; t - 2c = 2...........................(2)

(1) into (2) for c gives:

t - 2(t - 4) = 2

i.........e......... 8 - t = 2

so, t = 6 and c = 2

therefore, terrill is 6 and cranston is 2

and, in 2 years time they shall be 8 and 4....................................i..... terrill being twice cranston's age

i lost myself the first time i solved it

Cranston's Age: 2 years

Terril's Age: 6 years

Step-by-step explanation:

c = Cranston

t = Terril

Information we have:

c + 4 = t

t + 2 = 2c

So, if Cranston is 2 and Terril is 6, it's true as c + 4 (2 + 4) is 6 and When Cranston and Terril age 2 years, Cranston will be 4 and Terril will be 8, so Terril will be twice of Cranston's age.

*A lot of people forget the part where Cranston will ALSO age, so they get t = 10 and c = 6

Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81

Using Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)

Substituting the first three equations into the fourth allows us to solve for :

For each possible value of , we get two corresponding critical points at .

At these points, respectively, we get a maximum value of and a minimum value of .

Which equation represents a line that is perpendicular to the line y= 1/4x - 1 A) Y=-1/4x - 3
B) Y= 1/4X + 1
C) Y= 4X-5
D) Y= -4X - 2