# Calculate the mass of silver chloride required to plate 265 mg of pure silver.

Given Mass of pure silver (Ag) = 265 mg

Silver chloride AgCl which is used in plating silver contains 75.27 % Ag

This means that:

A 100 mg of silver chloride contains 75.27 mg of silver

Therefore, the amount of silver chloride required to plate a sample containing 265 mg silver would correspond to:

265 mg Ag * 100 mg AgCl/75.27 mg Ag

= 352.1 mg AgCl

0.35215 grams of silver chloride required to plate 265 mg of pure silver.

Explanation:

Mass of silver = 265 mg = 0.265 g

Moles of silver =

According to reaction, 2 moles of silver are obtained from 2 moles of silver chloride.

Then 0.002454 moles of silver will be obtained from :

of silver chloride

Mass of 0.002454 moles of silver chloride:

= 0.002454 mol × 143.5 g/mol = 0.35215 g

0.35215 grams of silver chloride required to plate 265 mg of pure silver.

## Related Questions

What is the total number of molecules in 11.2 liters of N2 gas at STP?

The number of molecules is 3,01E23 of N2

Explanation:

We use the formula PV=nRT, and STP: 1 atm of pressure and 273 K of temperature.

PV=nRT  ---> n=PV/RT

n= 1 atm x 11,2 l /0,082 l atm/ Kmol x 273K

n= 0, 5 mol

We use the number of Avogadro:

1 mol---------6, 02E23 molecules

0,5 mol----- x= (0,5 mol x6, 02E23 molecules)/ 1 mol = 3,01E23

What determines the path that an object in projectile motion follows?

Projectile motion is a form of motion where an object moves in a parabolic path; the path that the object follows is called its trajectory. Projectile motion only occurs when there is one force applied at the beginning of the trajectory, after which the only interference is from gravity. So, the trajectory is influenced by gravity and also by the air resistance.

Gravity

Explanation:

A projected object moves under the influence of gravity (acceleration at 9.8 m/s squared). The movement of the projected object takes a parabola shape, that is it undergoes vertical and horizontal motion.

The ksp of cadmium hydroxide, cd(oh)2, is 7.20 × 10-15. calculate the solubility of this compound in g/l.

When the solubility is the amount of solute that dissolved in a unit volume of the solvent.

and when the balanced reaction equation is:

so, by using the ICE table:

Cd(OH)2(s) ↔  Cd2+  +  2OH-

initial                               0             0

change                          +X           +2X

Equ                                  X             2X

so the Ksp expression = [Cd2+] [OH-]^2

and we have Ksp = 7.2 x 10^-15

and when we assume the solubility = X

by substitution:

7.2 x 10^-15 = (X) (2X)^2

7.2 x 10^-15 = X*4X^2

7.2 x 10^-15 = 4X^3

∴X = ∛(7.2x10^-15)/4

= 1.22 x 10^-5 M

∴ the solubility = X = 1.22 x 10^-5 M

What can you say about the strength of the intermolecular forces in neon and argon based on the critical points of Ne and Ar? (critical temperature (Ar)=150.9 K, critical pressure (Ar)=48.0 atm)

Explanation:

Since, it is given that critical temperature of Argon is 150.9 K and critical pressure of Argon is 48.0 atm.

It is known that gas phase of neon occurs at 50 K. As the boiling point of Ar is more than the boiling point of neon which means that there is strong intermolecular force of attraction between argon molecules as compared to neon molecules.

This is also because argon is larger in size. As a result, induced dipole-induced dipole forces leads to more strength in Ar as compared to Ne.