# When silver crystallizes, it forms face-centered cubic cells. The unit cell edge length is 408.7 pm. Calculate the density of silver in g/cm3?

the density of silver is calculated as

Data;

• edge length = 408.7pm
• atomic mass = 107.8682
• Avogadro's number = 6.022*10^23 atoms /mol

Density of Silver

The density of a substance is the ratio between the mass to the volume of that substance. In this case, the density of silver is calculated as

Let's substitute the values into the formula

From the calculations above, the density of silver is calculated as

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The density of silver can be calculated by using the following formula:

Here, m is mass and V is volume.

To calculate density, mass of silver needs to be calculated first.

In FCC, the number of Ag atoms in a unit cell will be 4, atomic mass of Ag is 107.87 g/mol and number of atoms in 1 mol are atoms, thus, mass can be calculated as follows:

.

Now, volume can be calculated as follows:

First convert pm to cm:

Thus,

Putting the value to calculate volume,

Now, calculate density as follows:

Therefore, density of silver is .

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