MATHEMATICS
HIGH SCHOOL

Answer:

The answer would be supply

Answer:

Answer:

C: Supply

Step-by-step explanation:

#PlatoFam !!!!

MIDDLE SCHOOL

If f(x)= 3x - 5 and the domain of f is (2, 4, 6), what is the range of f(x)

Answer:

f(x)

MIDDLE SCHOOL

What is 940 divided by 58 please help I'm doing my brothers homework xD

16 with the remainder 2

It is 16.208965517 you would then round the 8 and 0 the 0 is now a 1 so you answer is 16.21

MIDDLE SCHOOL

Write four numbers that round to 700,000 when rounded to the nearest hundred thousand

Answer:

The four numbers can be 699,999, 699,998, 699,997 and 699,996.

Step-by-step explanation:

Consider the provided number 700,000

According to place value.

Hundred Th. Ten Th. Thousands hundreds Tens Ones

100,000 10,000 1000 100 10 1

We need write four numbers that round to 700,000 when rounded to the nearest hundred thousand.

The rule of rounding a number is:

If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

If 5, 6, 7, 8, or 9 follow the number, then rounding digit rounds up by one number.

To find the number when rounded to the nearest hundred thousand gives 700,000 simply subtract 1, 2, 3, and 4 from the provided number.

Let us subtract 1 from 700,000 that will gives us:

700,000-1=699,999

700,000-2=699,998

700,000-3=699,997

700,000-4=699,996

If we round the above four number to the nearest hundred thousand it gives 700,000. because the number at the ten thousand place is 9, so to round up the number increase the digit of hundred thousand place by 1.

The digit at the hundred place is 6 so increase it by 1. i.e 7

Rounding up will gives us 700,000.

Thus, the four numbers can be 699,999, 699,998, 699,997 and 699,996.

690000

650000

670000

680000

650000

670000

680000

HIGH SCHOOL

A rock is projected directly upward from ground level with an initial velocity of 90 ft/sec. After how many seconds will it return to the ground?

For this case we have the following equation of motion:

h (t) = -16t ^ 2 + 90t

Equaling the equation to zero we have:

-16t ^ 2 + 90t = 0

We look for the roots of the polynomial:

(t) (- 16t + 90) = 0

t1 = 0 (initial position)

t2 = 90/16 = 5.625 s (time it reaches the ground again)

Answer:

it will return to the ground in:

t = 5.625 s

h (t) = -16t ^ 2 + 90t

Equaling the equation to zero we have:

-16t ^ 2 + 90t = 0

We look for the roots of the polynomial:

(t) (- 16t + 90) = 0

t1 = 0 (initial position)

t2 = 90/16 = 5.625 s (time it reaches the ground again)

Answer:

it will return to the ground in:

t = 5.625 s