MATHEMATICS
COLLEGE

Answer:

YES, we ignore the negative answer because the lengths, height and distances cannot be negative.

We have the statement of Pythagoras theorem.

We have to investigate why do we ignore the negative answer while applying Pythagoras theorem.

What is Pythagoras theorem ?It states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of squares of the base and perpendicular. Mathematically-

According to the question -

YES, it is true that we ignore the negative values of answer while applying Pythagoras theorem. It is because the Pythagoras theorem is used to measure the length of the sides of a right angled triangle. Its applications in real life are also used to find the distance, length and height. These quantities cannot be negative.

Hence, we ignore the negative answer because the lengths, height and distances cannot be negative.

To solve more questions on Pythagoras theorem, visit the link below -

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Answer:

The Pythagorean Theorem tells us how the lengths of a right triangle relate to each other, and we can't have negative lengths.

HIGH SCHOOL

The area of a rectangle is 56 cm. The length is 2cm more than x and the width is 5 cm less than twice x.Solve for x

Area of a rectangle is A = L*W.

Here, A = 56 cm^2 (not 56 cm).

= (56 cm^2)=( L )( W ) = (x+2)*(2x-5) = 2x^2 - 5x + 4x - 10

Simplifying, 2x^2 - 5x + 4x - 10 = 56, or 2x^2 - x - 66 = 0.

Solve this using the quadratic formula:

-(-1) plus or minus sqrt ( (-1)^2 - 4(2)(-66) )

x = -------------------------------------------------------------

2(2)

Finish the work: find x. Most likely you will need to check both of the roots. Keep in mind that x will likely be a positive number.

Here, A = 56 cm^2 (not 56 cm).

= (56 cm^2)=( L )( W ) = (x+2)*(2x-5) = 2x^2 - 5x + 4x - 10

Simplifying, 2x^2 - 5x + 4x - 10 = 56, or 2x^2 - x - 66 = 0.

Solve this using the quadratic formula:

-(-1) plus or minus sqrt ( (-1)^2 - 4(2)(-66) )

x = -------------------------------------------------------------

2(2)

Finish the work: find x. Most likely you will need to check both of the roots. Keep in mind that x will likely be a positive number.

MIDDLE SCHOOL

PLEASE HELP!!!!! Camilla borrows a book from the library for d days. The library charges a late fee of 0.10 dollars per day that the book is late.

If Camilla returns the book more than 21 days after she borrowed it, the expression 0.10(d-21), represents the total late fee Camilla owes.

What does (d-21) represent in this context?

Choose 1 answer:

(Choice A)

The number of days Camilla borrows the book

(Choice B)

The late fee Camilla owes per day the book is late

(Choice C)

The late fee Camilla owes per day she borrowed the book

(Choice D)

The number of days the book is late

Answer: Choice D

Step-by-step explanation: Why? Because (d-21) is what how many days she was late. The problem is asking what (d-21) presents and Choice D says 'The number of days the book is late'. If the problem did have the 0.10 before (d-21) THEN it would've been Choice C.

COLLEGE

it takes mike 18 minutes to finish reading. four pages how long does it take for him to finish reading 30 pages

It takes 135 minutes or 2 hours and 15 minutes to finish reading 30 pages.

135 minutes since every page is 4.5 minutes long to read

COLLEGE

City A is due north of City B. Find the distance between City A (36 degrees 6 prime36°6′ north latitude) and City B (21 degrees 42 prime21°42′ north latitude). Assume that the radius of Earth is 3960 miles. The distance between City A and City B is how many miles?

Answer:

distance = 994.75 miles

Step-by-step explanation:

given data

City A = 36°6′ = 36° + = 36.1° = 36.1° × = 0.6297 rad

City B = 21°42′ = 21° + = 21.7° = 21.7° × = 0.3785 rad

multiply by π/180 to convert the degree to radian

radius of Earth = 3960 miles

to find out

distance between City A and City B

solution

we first get here central angle between A and B city is

central angle between A and B city = 0.6297 rad - 0.3785 rad

and

now by arc length so we get distance

distance = 3960 miles × (0.6297 rad - 0.3785 rad )

distance = 994.75 miles