# Write the first six terms of the arithmetic sequence with the given first​ term, a 1​, and common​ difference, d.

The first six terms of the arithmetic sequence with the given first​ term​ and common​ difference is 200, 210, 220, 230, 240 and 250.

What is an arithmetic sequence?

An arithmetic sequence is a sequence of numbers where the differences between every two consecutive terms is the same. The general form an arithmetic sequence is an=a+(n-1)d

Given that, a₁​=200 and d=10.

a₁=200+(1-1)×10

= 200

a₂=200+(2-1)×10

= 200+10

= 210

a₃= 200+(3-1)×10

= 200+20

= 220

a₄= 200+(4-1)×10

= 200+30

= 230

a₅= 200+(5-1)×10

= 200+40

= 240

a₆= 200+(6-1)×10

= 200+50

= 250

Therefore, the first six terms of the arithmetic sequence with the given first​ term​ and common​ difference is 200, 210, 220, 230, 240 and 250.

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"Your question is incomplete, probably the complete question/missing part is:"

Write the first six terms of the arithmetic sequence with the given first​ term, a₁​, and common​ difference, d.

a₁​=200 and d=10.

## Related Questions

Whats an equation for -2x+4=7

x= -1 1/2

Step-by-step explanation:

move all term that don't contain x to the right side and solve

x = -3/2

x= - 1.5

x= -1 1/2

Help please this math is wack I am not having a good time d(1)=3
d(n)=d(n−1)−14
3rd term in the sequence

The third term is  -25.

Step-by-step expanation:

d(1)=3

From this equation, we know the first term is 3.

d(n)=d(n−1)−14

This looks like a recursive formula. It is used to find the next term.

n is the variable for the term number that you are solving for.

d(n-1) is the term value before the what you are looking for.

To find the 2nd term, use the formula and substitute values known:

d(n)= d(n−1)−14

d(2) = d(2-1) - 14

d(2) = d(1) - 14

We know d(1)=3

d(2) = 3 - 14

d(2) = -11

Find the third term using the same method:

d(n) = d(n−1)−14

d(3) = d(3−1)−14

d(3) = d(2)−14

d(3) = -11 - 14

d(3) = -25

The third term is  -25.

Step-by-step expanation:

d(1)=3

From this equation, we know the first term is 3.

d(n)=d(n−1)−14

This looks like a recursive formula. It is used to find the next term.

n is the variable for the term number that you are solving for.

d(n-1) is the term value before the what you are looking for.

To find the 2nd term, use the formula and substitute values known:

d(n)= d(n−1)−14

d(2) = d(2-1) - 14

d(2) = d(1) - 14

We know d(1)=3

d(2) = 3 - 14

d(2) = -11

Find the third term using the same method:

d(n) = d(n−1)−14

d(3) = d(3−1)−14

d(3) = d(2)−14

d(3) = -11 - 14

d(3) = -25

What is the upper quartile of the given data set 5,8,10,20,25,30,40,45
●35
●37.5
●37
●40

The median of the data would be (20+25)/2, which is 45/2 = 22.5.

The first quartile (Q1), the middle number between the smallest number and the median of the data set, is 9.

The second quartile (Q2) is the median of the data. (22.5)

The third quartile (Q3) the middle value between the median and the highest value of the data, is 35.

Hope this helped!

Which are the partial products for 2 x 2189?