# The following table shows the number of hours some students in two universities spend reading each week: School A 7 2 3 10 17 14 10 22 2 School B 9 10 16 18 20 15 17 18 14 Part A- Are the box plots symmetric? Justify your answer. (4 points)

Answer: They do not appear to be symmectric. they seem to line up well

## Related Questions

Isabel is running for president of the chess club, and she received 33 votes. There are 60 members in the club. What percentage of the club members voted for Isabel?

55%

Step-by-step explanation:

=(33/60)100%

=(11/20)100%

=(0.55)100%

=55%

Therefore, 55% of the club members voted for Isabel.

Carli and Angela share a cell phone plan and split the bill each month last month their bill was 109 Carli went over her limit on her phone so her share the bill was 15 more than Angela's account overrage charge which system of equations represents this situation A c+a=15
c=a+109

B c+a=109
c=a+15

C c-a=15
c=a+109

D c+a=109
a=c+15

B. Abigail used less than Carly and the total was 109.

D

Step-by-step explanation:

Beginning three months from now, you want to be able to withdraw \$1,900 each quarter from your bank account to cover college expenses over the next five years. if the account pays 0.41 percent interest per quarter, how much do you need to have in your bank account today to meet your expense needs over the next five years?

Compounding period = quarter (3 months)
Account interest per period (quarter), i = 0.41%
Number of periods over 5 years, n = 5*4 = 20
Quarterly withdrawal Amount, A = 1900
Initial deposit (today) = P

We match/equate the future value of the deposit and the withdrawals to calculate the deposit amount P needed.

Future value of deposit
F1=P(1+i)^n
=P(1.0041)^20

Future value of withdrawals
F2=A((1+i)^n-1)/i
=1900((1.0041^20-1)/0.0041

Equate F1=F2
P(1.0041)^20=1900(1.0041^20-1)/0.0041
=>
P=1900(1.0041^20-1)/0.0041/(1.0041^20)
=\$36412.15 (to the nearest cent)

Answer: A deposit of \$36412.15 is needed today to cover the future withdrawals.

What is the value of -5(3+4)