MATHEMATICS MIDDLE SCHOOL

What is 4^3 times 4^-5
A. 4^-15
B. 4^-2
C. 4^2
D. 4^8

Answers

Answer 1
Answer: 4^3=4*4*4=64
4^-5
==
=
==*64 =  
 Decimal: 0.0625 is your answer. 

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COLLEGE

Find all the values of x such that the given series would converge. ∑n=1∞(x−4)^n/4^n

Answers

The series is geometric, so it converges for


HIGH SCHOOL

Jen, carrie, and fran are each thinking of a number. when you add their numbers together you get 207. jen's number is 9 more than carrie's, and fran's number is 3 less than jen's number. what is fran's number?

Answers

Jen, carrie, and fran are each thinking of a number.

Let the number Jen thinks is J

Let the number Carrie thinks is C

Let the number Fran thinks is F

when you add their numbers together you get 207

so J + C + F = 207 -------------> Equation 1

jen's number is 9 more than carrie's

So J = 9 + C -------------> Equation 2

and fran's number is 3 less than jen's number

So F = J - 3

Replace 9 + C for J

F= 9 + C - 3 = 6 + C ------------> Equation 3

Replace equation 2 & 3 in equation 1

J + C + F = 207

9 + C + C + 6 + C = 207

3C + 15 = 207

3C = 192

Divide by 3 on both sides

C = 64

We know F = 6 + C = 6 + 64 = 70

So Fran's number = 70


MIDDLE SCHOOL

Is 17/31 greater than 19/14

Answers

Answer:

No

Step-by-step explanation:

Put both in your calculator. Do it in this order.

17

÷

31

=

0.5484

=========

Now do the next one

18

÷

14

=

1.357

19/14 > 17/31

MIDDLE SCHOOL

Susan is writing a linear equation for the cost of her cell phone plan. In the first month, she talks for 52 minutes and is charged $19.41. In the second month, she talks for 380 minutes and is charged $45.65. A) How much money does Susan's cell phone company charge for each minute? B) Write an equation that Susan can use to determine the cost of her cell phone plan, y, as it relates to the number of minutes used, x

Answers

Assuming that the cost per minute is the same for both months and the plan fee is the same, you can use y=mx+b for this

y is the cost of the phone plan, x is the cost per minute and b is the start cost.

so    19.41=25x+b for the first month
and  45.65=380x+b for the second month

solve both for b you get:
19.41-25x=b and 45.65-380x=b.  from this we get
19.41-25x=45.65-380x

solve for x

328x=26.24 and x=0.08

this means the cost per minute is 0.08c/min (answer A)

rewrite the equation to calculate b, and where this time, the x is the number of minutes talked.

y=0.08x+b and plug in one of the two months

45.65=0.08 * 380 + b

Solve for b and b is 15.25

so the final equation is

y=0.08x+15.25  (answer B)
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