MATHEMATICS MIDDLE SCHOOL

an object that weighs 10ib on earth would weigh only 4ib on mars if you weigh 95ib on earth how much would you weigh on mars

Answers

Answer 1
Answer: *I'm assuming ib is a typo for lb.

You can set up a proportion saying:


Cross multiply:



So, you would weigh 38 lbs on Mars if you weighed 95 lbs on Earth.

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MIDDLE SCHOOL

Identify the least common multiple of x2 − 10x + 24 and x2 − x − 12. \

Answers

Factor x^2 - 10x +24 = (x - 4)(x - 6)

Factor x^2 - x - 12 = (x - 4)(x + 3)

The common multiple is (x - 4)

HIGH SCHOOL

What is the length of the arc on a circle with radius 20 in. intercepted by a 15° angle? Use 3.14 for π .
Round the answer to the hundredths place.
Enter your answer in the box.
in.

What is the measure of the central angle of a circle with radius 24 ft that intercepts a 10 ft arc?
Use 3.14 for π .
Round the answer to the hundredths place.
Enter your answer in the box.

Answers

A. Since we know that formula to find arc length is:  

Therefore, the length of intercepted arc will be 5.23 in.

B. Since we know that formula to find central angle is:

Therefore, measure of central angle will be 23.89 degrees.


Length of arc  = (15/360) * 2*3.14*20  =   5.23  ins

circumference of the circle = 2*3.14*24 = 150.72

angle at center  from 10 ft arc  = (10/150.72)  * 360  = 23.89 degrees


HIGH SCHOOL

Rectangular box a has a greater volume than rectangular box and b but the length of box a is less than the length of box b. how is this possible?

Answers

Volume=length times width times height


it is possible for us to have a shorter length but have greater volume if the other 2 dimentions (width and height) are sufficiently great to compensate

example

box a is length 2, width 10 and height 20, volume is 400 cubic units
box b is length 3, width 4, and height 5, volume is 60 cubic units


the width and heigth must be greater
They must have had different widths
MIDDLE SCHOOL

Solve. 6(4 – x) + 6x = 24


A.all real numbers

B.4

C. –4

D. 0

Answers



First, you develop, and you get:


Then, you put known numbers apart (numbers without x), and unknown numbers apart (numbers with x), and remember that moving from a part to another change the sign of the number. So you get:


And now you operate, and u get:


Since we get the same number in the 2 parts ( the number 0), that means that the correct answer is A (all real numbers)

Hope this Helps! :)
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