MATHEMATICS
COLLEGE

Answer: Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,

MIDDLE SCHOOL

rectangle with a perimeter of 60 feet has a length and width in a ratio of 3:2. What are the length and width?

Total parts:

3+2= 5

Half of perimeter (or the sum of the length and the width) is:

60 ft/2= 30 ft

Each part is:

30 ft/ 5 parts= 6 ft/part

The length costs 3 parts, and the length is:

6 ft/ 1 part* 3 parts= 18 ft.

The width costs 2 parts, and the width is:

6 ft/ 1 part* 2 parts= 12 ft.

The length and the width of the rectangle are 18 ft and 12 ft respectively~

3+2= 5

Half of perimeter (or the sum of the length and the width) is:

60 ft/2= 30 ft

Each part is:

30 ft/ 5 parts= 6 ft/part

The length costs 3 parts, and the length is:

6 ft/ 1 part* 3 parts= 18 ft.

The width costs 2 parts, and the width is:

6 ft/ 1 part* 2 parts= 12 ft.

The length and the width of the rectangle are 18 ft and 12 ft respectively~

MIDDLE SCHOOL

Can 29/48 be simplified

29/48 Can not be simplefied... Nothing will go into 48 that can also go into 29.

So 29/48 Is your final answer.

So 29/48 Is your final answer.

Well actually we can't simplified or reduce more the final answer is 29/48 :)

HIGH SCHOOL

Please help! Determine if the function shows a linear relationship or an absolute value relationship. Then evaluate the function for the indicated value of x.

a. f(x) = |x – 3| – 2; x = –5

b. g(x) = 1.5x; x = 0.2

c. p(x) = |7 – 2x|; x = –3

Answer:

(a) Absolute value relationship, f(-5)=6

(b) Linear relationship, g(0.2)=0.3

(c) Absolute value relationship, p(-3)=13

Step-by-step explanation:

A modulas function always represents an absolute value relationship.

A polynomial function with degree 1 is always represents a linear function.

(a)

The given function is

It is a modulas function, so it represents an absolute value relationship.

Substitute x=-5 in the given function.

Therefore the value of function at x=-5 is 6.

(b)

The given function is

It is a linear function, so it represents a linear relationship.

Substitute x=0.2 in the given function.

Therefore the value of function at x=0.2 is 0.3.

(c)

The given function is

It is a modulas function, so it represents an absolute value relationship.

Substitute x=-3 in the given function.

Therefore the value of function at x=-3 is 13.

I think it’s b:g(x)=1.5x; x=0.2

COLLEGE

Jim borrows $14,000 for a period of 4 years at 6 % simple interest. Determine the interest due on the loan. [4 marks

Answer: $ 3,360

Step-by-step explanation:

Given : The principal amount borrowed for loan :

Time period :

Rate of interest :

The formula to calculate the simple interest is given by :-

Hence, the interest due on the loan = $ 3,360