# The classes at the middle school want to raise money. The sixth grade runs a bake sale for 55 hours and makes \$170. The seventh grade sets up a dunking booth for 4 hours and makes \$112. The eighth grade has a car wash and makes \$192 in 6 hours. Which class has the highest rate for raising money?

Answer: The 8th grade does. All you do is divide each number by the amount of hours worked. So 6th grade 170/55 7th 112/4 and 8th 192/6
In the end its 6th= 3 dollars an hour 7th= 28 dolars an hour and 8th gets 32dollars an hour so they have the highest rate
Therefore 8th grade has the highest rate for making money.You divide the money earned by the number of hours worked.

## Related Questions

they are serving hot dogs at the end of year party hot dogs are sold in packs of 8 if they want to have one hot dog for each of the 63 guests how many packs of hot dogs do they need to buy

You must buy 8 packs of hot dogs

The conversion factor relating feet to meters is 1ft=0.305m. Keep in mind that when using conversion factors, you want to make sure that like units cancel leaving you with the units you need.. You have been told that a certain house is 164 m2 in area. How much is this in square feet?

we are asked in the problem to determine the converted value of 164 m2 area in terms of square feet. It is given that 1 ft is equal to 0.305 meters. In this case, the solution is 164 m2 * (1ft/ 0.305 m)2 equal to 1762. 97 ft2. The final answer is equal to 1762. 97 ft2

Identify the null and alternative hypothesis in the following scenario. To determine if battery 1 lasts longer than battery 2, the mean lasting times, of the two competing batteries are compared. Twenty batteries of each type are randomly sampled and tested. Both populations have normal distributions with known standard deviations Select the correct answer below

H₀: μ ≤ μ  H₁: μ > μ

Step-by-step explanation:

Hello!

If battery 1 lasts longer than battery 2, and all the batteries of population 1 and population 2 are built using the same method, then you could say that the population mean of the lifespans of batteries 1 are longer than the lifespan of batteries 2. Symbolically: μ₁ > μ₂

This would be your alternative hypothesis.

The null hypothesis is:

H₀: μ₁ ≤ μ₂

Then the correct answer is number 5

Looked for exercise's Options

H₀: μ ≥ μ H₁: μ < μ

H₀: μ ≤ -μ  H₁: μ > -μ

H₀: μ ≥ -μ  H₁: μ < -μ

H₀: μ = μ  H₁: μ ≠ μ

H₀: μ ≤ μ  H₁: μ > μ

Sania has some money in her account. Every month, she uses the same amount of money from her account to pay for her dance classes. The table below shows the amount of money left in her account after a certain amount of time, in months: Sania's Savings

Month (x)

Amount (dollars) (y)

0

150

1

110

2

70

3

30

What is the value of the rate of change of the function for this table and what does it represent in this situation?
−\$40 per month; the amount of money withdrawn per month
\$40 per month; the initial amount of money in the account
−\$150 per month; the amount of money withdrawn per month
\$150 per month; the initial amount of money in the account

150-110 = 40

rate of change would be -40, the amount withdrawn every month

The value of the rate of change of the function for this table is −\$40 per month and it represents the amount of money withdrawn per month.

What is the rate of change per month?

Looking at the given table, it can be seen that the amount in the account declines every month. The value of the account would decline when money is withdrawn from the account.

Rate of decline  = money in month 1 - money in month 2

150 - 110 = \$40