MATHEMATICS HIGH SCHOOL

Mrs. Sage will print a copy of the class alphabet book for each student. The book is formatted in1/2 pages with a title page, a page for each letter and an end page. If there are 70 students, how many reams of paper will Mrs. Sage need for the books?

Answers

Answer 1
Answer: Note that
1 ream of paper  = 500 sheets (or pages printed)

Each book has
1/2 page for each letter of the alphabet = (1/2)*26 = 13 pages
A title page = (1/2)*1 = 1/2 page
An end page = (1/2)*1 = 1/2 page

Total pages per book = 13 + 1/2 + 1/2 = 14 pages.
There are 70 students, therefore the number of pages needed is
14*70 =  980 pages

The number of reams of paper required is
980/500 = 1.96 ≈ 2 reams

Answer: 2 reams


Related Questions

MIDDLE SCHOOL

Write an expression for 8 times x

Answers

8x

8(x)

Either one works ^^

an expression would be 8x because 8 times x equals 8x

MIDDLE SCHOOL

What's bigger 9/10 or 4/5

Answers

To be able to compare 2 fraciton we have to make common denominator and then we can just compare numerators. 

Now we can compare numerator from the first (9) and from the second fraction (8)
9>8, so the bigger is 9/10
9/10 because smaller pieces and has more of them
HIGH SCHOOL

Find the second of 3 consecutive integers if the sum of the first and the third is 26

Answers

X= 1st integer
x+1= 2nd integer
x+2= 3rd integer

Add the 1st and 3rd set equal to 26.

x + (x+2)= 26
combine like terms
2x + 2= 26
subtract 2 from both sides
2x= 26
divide both sides by 2
x= 13

Substitute x=13 to find 2nd integer.
= x+1
= 13 + 1
= 14 second integer

ANSWER: The second integer is 14.

Hope this helps! :)
COLLEGE

Find the value of the expression below. log4 3 + log4 8 - log4 6

Answers

The question can be solved as:

log4^3 + log4^8 - log4^6
= 3log4 + 8log 4 - 6 log4
(Because log n ^ m = m log n)
= 5 log 4
= 5log (2^2)
(Because 4 can be written as 2^2)
= 5*2 log 2
= 10 log 2
= 10*0.3010
(Because log 2 = 0.3010)
= 3.010

1 . . . . . . . . .. . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . .. . . . . . .

Random Questions