# △XYZ was reflected over a vertical line, then dilated by a scale factor of 1/2, resulting in △X'Y'Z'. Which must be true of the two triangles? Check all that apply. △XYZ ~ △X'Y'Z' XZY ≅ Y'Z'X' YX ≅ Y'X' XZ = 2X'Z' mYXZ = 2mY'X'Z'

## Answers

Answer 1
Answer: Given that the triangle XYZ was reflected over a vertical line, then dilated by a scale factor of 1/2, resulting in triangle X'Y'Z'. The true statement is:
triangle XYZ is similar to X'Y'Z
YX is similar Y'X'
XZ=2X'Z'
The above are the true statements.
Answer 2
Answer:

The options that are true about the two triangles are; △XYZ ~ △X'Y'Z';

XZY ≅ Y'Z'X' and XZ = 2X'Z'

How to Solve Transformation Problems?

W are told that △XYZ is reflected over a vertical line, then dilated by 1/2 to form X'Y'Z'. This means that;

X'Y'Z' = ¹/₂XYZ

i.e. the side lengths of triangle X'Y'Z' is half the side lengths of the original triangle XYZ

Thus, we can say that:

The triangles are similar

The angles are congruent.

The side lengths of XYZ are twice the side lengths of X'YZ'.

Read more about Transformations at; brainly.com/question/4289712

#SPJ5

## Related Questions

What is the pythagorean theorem formula

### Answers

pythagorean theorem formula=  a^{2}+ b^{2}= c^{2}

The formula is A^2+B^2=C^2.

An example of using to solve a problem is below.

Let's say we have a right triangle with a and b given but we are missing c.

A and B are called "Legs" While C is called the Hypotenuse.

A= 12 and B= 16.

Lets solve it.

Thus, our final answer is 40.

Please Help!! The answer is your own opinion! Describe what you find difficult about factoring and what you find easy. Next, compare factoring to graphing as a way to solve a quadratic equation. Which method do you prefer and why?

### Answers

I found nothing difficult in factoring as calculator would do the work while graphing is too troublesome for a few marks worth of question
i prefer factoring
The only thing I found difficult in factoring was the difference of two squares, but factoring was easy because you can plug it all into the calculator. Graphing is easy because you just type the equations in and find whatever you need to find via 2nd trace

Four expressions are shown below: 4(8x + 2)
4(7x + 3)
32x + 8
28x + 12

Which two expressions are equivalent to 4(7x + 2 + x)?

### Answers

It’s the first one and the third one

Answer: A and C

Step-by-step explanation:

During an experiment, some water was removed from each of the 6 water tanks. If the standard deviation of the volumes of water in the tanks at the beginning of the experiment was 10 gallons, what was the standard deviation of the volumes of water in the tanks at the end of the experiment? (1) For each tank, 30% of the volume of water that was in the tank at the beginning of the experiment was removed during the experiment.
(2) The average (arithmetic mean) volume of water in the tanks at the end of the experiment was 63 gallons.

### Answers

Answer:

First statement is correct.

Step-by-step explanation:

If we add or subtract a constant to each term in a set:  Mean will increase or decrease by the same constant.  Standard Deviation will not change.

If we increase or decrease each term in a set by the same percent (multiply all terms by the constant):  Mean will increase or decrease by the same percent.  Standard Deviation will increase or decrease by the same percent.

For example:

Standard Deviation of a set: {1,1,4} will be the same as that of {5,5,8} as second set is obtained by adding 4 to each term of the first set.

That's because Standard Deviation shows how much variation there is from the mean. And when adding or subtracting a constant to each term we are shifting the mean of the set by this constant (mean will increase or decrease by the same constant) but the variation from the mean remains the same as all terms are also shifted by the same constant.

So according to this rule, statement (1) is sufficient to get new Standard Deviation, it'll be 30% less than the old.. As for statement (2) it's clearly insufficient as knowing mean gives us no help in getting new Standard Deviation.